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Tightening torque and screw loads

Calculate the tightening torque and the maximum permissible preload of a steel or stainless steel metric screw, following VDI 2230. You can compare several cases side by side. Everything updates instantly with each input.

To compare cases side by side, open the page on a computer or a tablet.

Data

Screw head
Size
Pitch
Screw property class
Screw finish
Lubrication
Tool
This covers tightening only (steps R1, R7, R10 and R13 of VDI 2230), not the load in service, settling or fatigue. The check of the part under the head is in the Advanced mode.

Results

TF

Tightening torque

36.4N·m

Clamping force (preload)

31.1kN

How the torque is shared

Creates the clamping force
20%
Friction in the thread
36%
Friction under the head
44%

Tightening

Smallest preload to expect
15.5kN
Lowest torque the tool may give
34.9N·m
Highest torque the tool may give
37.8N·m
Only 20 % of the torque goes into the clamping force. The rest goes in friction. That is why lubrication affects the result so much.

Tightening torque: 36.4 N·m

A design guide, based on the standards listed below. For critical joints, check against them or with a specialist.

Partly verified data

We have checked part of this data against reliable sources. The values marked with a have fewer sources than we require: use them as a guide and check them (they may not appear in this view).MechLab Geek accepts no liability for any use of this data or its consequences. Check it before you use it. Legal notice.Spotted a mistake? Let us know.

How this calculator works

This calculator lets you work out the torque and the preload of a screw according to VDI 2230, the reference guideline for calculating bolted joints.

You choose the screw, its finish, the lubrication and the tool. You get the wrench torque with its tolerance, the minimum preload to expect with that tool, the pressure under the head against what the part withstands, and the proof and breaking loads of the screw.

Assumptions and limitations

Scope

  • Tightening during assembly only: one screw tightened by torque, at room temperature.
  • Full-shank metric screw. The maximum preload brings it to 90 % of its yield strength.
  • The pressure under the head, under static load, is compared with what the material of the part withstands.
  • Proof and breaking loads are of the screw alone, not of the joint.

Simplifications

  • Friction is constant during tightening; a friction class takes its lowest value.
  • The washer changes the hole and limits the bearing, but does not spread the load: a wider one does not lower the pressure shown.
  • The tool tolerance is that of the instrument alone, without the scatter of the friction, and assumes a click-type torque wrench (type II).
  • In the reverse mode, the band is that of the friction class, without the scatter of the wrench.

Out of scope

  • Operating load, embedding, joint stiffness and fatigue.
  • Thread stripping, locking nuts or patches, coatings and retightening.

Sources: VDI 2230 values come from reproductions by manufacturers (Bossard, Würth, Reyher, Schaeffler), not from the guideline itself; the results match their tables to within 1 %.

What VDI 2230 is

VDI 2230 is a guideline developed by the Verein Deutscher Ingenieure (the Association of German Engineers) that explains how to calculate bolted joints systematically.

Before it appeared, general rules and wide safety margins were used. VDI 2230, by contrast, starts from a mathematical model that treats the bolted joint as an elastic system of springs, accounting for every force, deformation and friction involved.

It was first published in 1974 and has been revised several times since. Today it is widely used as the reference technical guide for calculating bolted joints.

How the guideline works

The guideline proposes a systematic step-by-step calculation (R1 to R13) that starts from the loads acting on the joint and checks that the screw and the parts withstand them, from assembly to service.

How this calculator applies it

This calculator does not apply the method step by step, since it does not start from a joint design and known loads. What it does is provide the torque and the preload for a given screw, using the mathematical models of steps R1, R7, R10 and R13 of VDI 2230.

Formulas and fundamentals

This section is for those who like to understand the sense of things. Here we develop, step by step, the tightening theory of the VDI 2230 method.

What we are after

A screw can be seen as a very stiff spring. When we tighten it, we force it to stretch a little. And as it tries to regain its shape, it pulls on the parts it holds and clamps them against each other.

≈
A screw behaves like a very stiff spring.

We call that force the preload, FF, and it is what holds the joint: it stops the parts separating or slipping and the screw coming loose.

In practice we usually cannot measure the force inside a screw. But what we can measure is the tightening torque on the wrench, MA\MA. Almost everything that follows is translating from that torque to that force.

First we will see how much torque a preload costs. Then, how much preload a screw can take. And last, what happens when the tightening torque is not exact.

The torque in the thread

A thread is a ramp in the shape of a helix.

If we unroll one turn of thread, we get an inclined plane. This plane rises a height equal to the pitch PP, and runs a perimeter of π d2\pi\,d_2, where d2d_2 is the mean diameter of the thread flanks.

If we represent the screw as an object on that ramp, we can say that turning the screw is equivalent to pushing the object up the ramp with a force HH.

F H N µG N π d2 P
One turn of thread unrolled, with the forces on the screw. The scale is exaggerated: the real pitch is far smaller than the perimeter.

The drawing shows all the forces acting on the screw: the preload FF, the push HH, the normal force NN, with which the ramp supports the screw, and the friction, which opposes the motion.

Writing the equilibrium of forces, we get:

Hcos⁡α=Fsin⁡α+μG NN=Fcos⁡α+Hsin⁡αH\cos\alpha = F\sin\alpha + \muG\,N \qquad N = F\cos\alpha + H\sin\alpha

where

HH
Tangential push that lifts the screw up the ramp
α\alpha
Helix angle: the slope of the ramp, with tan α = P / (π d₂)
NN
Normal force with which the flank supports the screw
μG\muG
Friction coefficient between the thread flanks

Solving for the push, we arrive at:

H=F tan⁡α+μG1−μG tan⁡αH = F\,\frac{\tan\alpha + \muG}{1 - \muG\,\tan\alpha}

However, the ramp is very gentle (α\alpha is about 3°) and μG\muG is around 0.15, so the product μG tan⁡α\muG\,\tan\alpha is tiny and the denominator is almost 1. So we can simplify it like this:

H≈F(Pπ d2+μG)H \approx F\left(\frac{P}{\pi\,d_2} + \muG\right)

One more effect is missing: the metric thread has its flank tilted 30° from the axis (60° between flanks). It is not a straight ramp, it is a wedge. So the real normal force NN grows by a factor 1/cos⁡30∘=1.1551 / \cos 30^\circ = 1.155, and the friction with it. It is enough to replace μG\muG with 1.155 μG1.155\,\muG:

H=F(Pπ d2+1.155 μG)H = F\left(\frac{P}{\pi\,d_2} + 1.155\,\muG\right)

A torque is a tangential force times the radius it acts at, and HH acts at the mean radius d2/2d_2 / 2. So the torque in the thread is:

MG=H d22=F d22(Pπ d2+1.155 μG)≈F(0.16 P+0.58 d2 μG)\MG = H\,\frac{d_2}{2} = F\,\frac{d_2}{2}\left(\frac{P}{\pi\,d_2} + 1.155\,\muG\right) \approx F\left(0.16\,P + 0.58\,d_2\,\muG\right)

where

MG\MG
Torque in the thread: what has to be applied to the screw to turn it up the thread

Let us look at how it comes out: the preload FF times two coefficients, which are the two effects we have seen.

0.16 P0.16\,P: the slope. It is the torque it costs to climb the ramp without friction and, so, the one that really stretches the screw. It is tiny, a fraction of the pitch.

0.58 d2 μG0.58\,d_2\,\muG: the friction of the flanks. It is the torque lost overcoming it: it stretches nothing, and grows with the coefficient μG\muG and with the diameter d2d_2.

The torque at the head

Besides the torque in the thread, there is another one to account for: the one produced by the friction of the head turning against the bearing surface.

No equilibrium is needed here: the normal force is simply the preload FF, so the friction force is μK F\muK\,F. This force acts at the mean diameter of the bearing ring, DKm\DKm (the average of the bearing diameter and that of the hole), that is, at a radius DKm/2\DKm / 2. Its torque is, as before, force times radius:

DKm=dw+dh2MK=F DKm2 μK\DKm = \frac{\dw + \dh}{2} \qquad \MK = F\,\frac{\DKm}{2}\,\muK

where

μK\muK
Friction coefficient between the head and the part
dw\dw
Bearing diameter of the head
dh\dh
Diameter of the clearance hole
DKm\DKm
Mean diameter of the bearing ring
MK\MK
Torque under the head

The torque needed

Now it only remains to add the torque of the thread, MG\MG, and that of the head, MK\MK.

Key formula
MA=MG+MK=F(0.16 P+0.58 d2 μG+DKm2 μK)\MA = \MG + \MK = F \left(0.16\,P + 0.58\,d_2\,\muG + \frac{\DKm}{2}\,\muK\right)

This is the formula that gives the torque, and now we know where each term comes from: 0.16 P0.16\,P is the one that stretches the screw, 0.58 d2 μG0.58\,d_2\,\muG is the friction in the thread and DKm/2⋅μK\DKm / 2 \cdot \muK is that of the head.

With usual frictions, only about a tenth of the torque stretches the screw; the rest is lost to friction. That is why lubrication changes so much: with the same torque, less friction leaves more torque for stretching and the preload goes up.

TF
  • Stretches the screw≈ 10 %
  • In the thread≈ 40 %
  • Under the head≈ 50 %
Where the tightening torque goes. The percentages are indicative; the calculator gives those of each case.

The K factor shortcut

In some tables and calculators, a much more compact version of the torque equation we have seen is used:

MA=K F d\MA = K\,F\,d

where

KK
Torque factor
dd
Nominal diameter of the screw

That factor KK comes from dividing the tightening torque by F dF\,d:

K=MAF d=0.16 Pd+0.58 d2d μG+DKm2 d μKK = \frac{\MA}{F\,d} = 0.16\,\frac{P}{d} + 0.58\,\frac{d_2}{d}\,\muG + \frac{\DKm}{2\,d}\,\muK

The ratios P/dP/d, d2/dd_2/d and DKm/d\DKm/d change little from one size to another, so KK depends mostly on the frictions. That is why a single value, near 0.2, works for dry or lightly oiled screws and is far off in other conditions.

In this calculator we do not use KK to calculate the torque. We think that, while KK can be useful for quick manual calculations, it is not worth using when the full model is at hand.

However, we give it as a result, so you can compare it with other tables and calculators.

How far it can be tightened

A screw takes what its section takes. The part that really works is called the stress area, and it is tabulated for each thread.

The tensile stress is the preload spread over that area:

σ=FAs\sigma = \frac{F}{\As}

where

σ\sigma
Tensile stress in the screw
As\As
Stress area of the screw

The material is given by the property class. In steels, the first number of “8.8” times 100 is the tensile strength Rm\Rm in MPa (800), and the product of the two numbers times 10 is the yield strength Rp0.2\Rp (640 MPa): the stress beyond which the screw no longer returns to its shape.

The name comes from how it is measured: R is strength, p permanent deformation, and 0.2 the 0.2 % of elongation left after unloading the screw.

Tightening right up to the yield strength would be a gamble: no margin would be left for the working load or the scatter of the tightening. VDI 2230 proposes using only a part ν\nu of it, 90 % in its tables:

σ≤ν Rp0.2\sigma \le \nu\,\Rp

where

ν\nu
Fraction of the yield strength that is used
Rp0.2\Rp
Yield strength of the screw

But something is still missing: when tightened, the screw is not only stretched.

Stretching and twisting at once

The torque in the thread, MG\MG, does not only stretch the screw: it also twists it.

This torque produces a shear stress τ\tau in the section. For a stress area of diameter d0d_0 and an elastic material, it would be τ=16 MG/(π d03)\tau = 16\,\MG / (\pi\,d_0^3). VDI 2230 lowers it to three quarters, because with the screw at its limit the material starts to yield and the twist is shared better. Divided by the tensile stress σ=F/As\sigma = F / \As, the factor for the elastic case is 2; with that reduction, 1.5:

τσ=1.5 d2d0(Pπ d2+1.155 μG)\frac{\tau}{\sigma} = 1.5\,\frac{d_2}{d_0}\left(\frac{P}{\pi\,d_2} + 1.155\,\muG\right)

The bracket is H/FH / F, the push of the thread per unit of preload: the friction of the flanks not only costs torque, it also twists the screw.

where

τ\tau
Shear stress produced by the twist
d0d_0
Diameter of the circular section with the area of the stress area

Tension and shear act together, and combine into an equivalent stress, von Mises, which is the one compared with the yield strength:

σred=σ2+3 τ2=σ 1+3(τσ)2\sred = \sqrt{\sigma^2 + 3\,\tau^2} = \sigma\,\sqrt{1 + 3\left(\frac{\tau}{\sigma}\right)^2}

where

σred\sred
Equivalent von Mises stress

If we ask it not to exceed ν Rp0.2\nu\,\Rp and solve for the tension, we get the permitted one. Times the stress area, it is the maximum preload:

Key formula
σM zul=ν Rp0.21+3(τσ)2FM zul=σM zul As\sMzul = \frac{\nu\,\Rp}{\sqrt{1 + 3\left(\frac{\tau}{\sigma}\right)^2}} \qquad \FMzul = \sMzul\,\As

where

σM zul\sMzul
Maximum permitted tension when tightening
FM zul\FMzul
Maximum permitted preload

The more friction in the thread, the more twist and the less tension fits: the permitted preload goes down.

The wrench is not perfect

Everything above assumes we know the frictions and the wrench hits its mark. Neither is quite true: with the same torque, two identical screws end up with different preloads, mostly because the friction varies from one to the other.

The tightening factor says how far apart the largest and the smallest possible preload are. The more precise the method, the closer to 1 it is:

αA=FM maxFM min\alphaA = \frac{\FMmax}{\FMmin}

where

αA\alphaA
Tightening factor
FM max\FMmax
Largest preload that can result
FM min\FMmin
Smallest preload that can result

We aim for the largest to be the permitted one, so as never to overshoot. The smallest is then:

Key formula
FM min=FM zulαA\FMmin = \frac{\FMzul}{\alphaA}

With αA=2\alphaA = 2, the preload can end up at half of the calculated one. That is why the joint must work with the smallest, not the largest.

So the parts are not crushed

The whole preload rests on the ring under the head, between the bearing diameter and the hole. Its area is that of the large circle minus that of the hole:

Ap=π4(dw2−dh2)\Ap = \frac{\pi}{4}\left(\dw^2 - \dh^2\right)

where

Ap\Ap
Area of the bearing ring

The pressure on the part is the preload over that area, and must not exceed what the material takes:

p=FAp≤pGp = \frac{F}{\Ap} \le \pG

where

pp
Pressure on the part under the head
pG\pG
Limit pressure the material takes

If it does, the head sinks into the part and the joint loses preload. A washer enlarges the bearing, but this calculator does not count that and is therefore conservative (see “Assumptions and limitations”).

The loads of the property class

These are loads of the screw alone, not of the joint: the stress area times the stress of each level. In steel, the proof load uses the proof stress of the property class; in stainless steel, the yield strength.

Fp=As SpFp0.2=As Rp0.2Fm=As Rm\Fp = \As\,\Sp \qquad \Fpz = \As\,\Rp \qquad \Fm = \As\,\Rm

where

Fp\Fp
Proof load
Fp0.2\Fpz
Load at the yield strength
Fm\Fm
Breaking load
Sp\Sp
Proof stress of the property class

So far, the tightening. What happens when the joint works, with external loads, the stiffness of the parts or fatigue, is left out. What this calculator takes for granted is in “Assumptions and limitations”.

References

The parts

The method and the holes

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